Given 5 different green dyes, 4 different blue dyes and 3 different red dyes, the number of combination of dyes taking atleast one green dye and one blue dye, is

• Given 5 different green dyes, 4 different blue dyes and 3 different red dyes, the number of combinations of dyes which can be chosen taking at least one green and one blue dye is given by
  (2^5-1)*(2^4-1)*(2^3)=3720
• 12 years agoHelpfull: Yes(18) No(2)
• Answer: The least number of dyes that a combination can have is 2.
  (one blue and one green).
  
  Maximum number of dyes that a combination can have is 12
  (5G, 4B, 6R).
  
  Atleast one green dye can be selected out of 5 green dyes. The number of ways is
  
  
  
  After selecting one or more green dyes, we can select atleast one blue dye out of 4 different blue dyes. The number of ways is
  
  
  After selecting atleast one green dye and atleast one blue dye, at least one red dye or no red dye can be selected in
  
  = 1 + 3 + 3 + 1 = 8 ways
  
  The total number of combinations (31)(15)(8) = 3720.
  
  
• 12 years agoHelpfull: Yes(13) No(2)
• formula for choosing atleast one n1 and n2 number of things and any number of n3 things is (2^n1 -1)*(2^n2-1)*(2^n3)=31*15*8=3720 ...........thnku :)
• 12 years agoHelpfull: Yes(13) No(1)
• total 12 dyes!!..2 dyes to pick = 12c2 = 66.
  
  atleast 1 green = 5c1 = 5.
  
  atleast 1 blue = 4c1 = 4.
  
  the equation is (5c1 + 4c1)/12c2 = 9/66 = 3/22 ans!!
• 12 years agoHelpfull: Yes(8) No(23)
• total number of dyes = 12
  thus selecting two dyes of 12 = 12c2 = 66
  
  for selecting one dye of 5 green = 5c1=5
  similarly for one dye of 4 blues = 4c1=4
  
  therefore, selecting 1 blue AND 1 green = 4c1 * 5c1
  = 4*5
  =20
  thus, 20/66= 10/33
• 12 years agoHelpfull: Yes(5) No(10)
• no of ways of selectng atleat 1 green dye is
  5c1+5c2+5c3+5c4+5c5=31
  no of ways of selectng atleast 1 blue dye is 4c1+4c2+4c3+4c4=15
  
  no of ways of selecting 0 or mor red dyes is 1+3+3+1=8
  so ewe get 31*15*8=3720
  
• 12 years agoHelpfull: Yes(5) No(1)
• selecting one green dye from 5 is 5c1=5
  selecting one blue dye from 4 is 4c1=4
  selecting 2 dyes from total 12 dyes is 12c2=66
  5+4/66=3/22
• 12 years agoHelpfull: Yes(4) No(9)
• selecting 1 green and 1 blue=5*4=20 combinations
  selecting remaining 10 different dyes=2^10=1024 combinations
  total possibilities=1024*20=20480 combinations
• 12 years agoHelpfull: Yes(2) No(5)
• ans is >=9.we have to add the highest of two numbers because for example if we take 7 it may be 4 blue and 3 red or if we take 8 it may be 5 green and 3 red so the min value is 9.
• 12 years agoHelpfull: Yes(1) No(6)
• selecting 1 green and 1 blue=5*4=20
  selecting remaining 10 different dyes=2^10=1024
  total possibilities=1044
• 12 years agoHelpfull: Yes(1) No(6)
• ans: here the combination dyes to select that is 2 or 3 not mentioned.
• 12 years agoHelpfull: Yes(1) No(6)
• @ pavan plz explain 1+3+3+1
• 12 years agoHelpfull: Yes(1) No(2)
• 5*4*4. as because we can take 1-4 no of blue dyes,1-5 nos of green dyes & 0-3 nos of red dyes.
• 12 years agoHelpfull: Yes(0) No(7)