In a city 20 percent of the population travels by car, 50% travels by bus and 10% travels by both car and bus. Then persons travelling by car or bus is.

• 
  Let x be the total number of population
  then according to the problem,
  p(car)=20% of x=x/5
  p(bus)=50% of x=x/2
  p(car ∩ bus)=10% of x=x/10
  since,
  p(car ∪ bus)=p(car)+p(bus)-p(car ∩ bus)
  p(car ∪ bus)=x/5 + x/2 - x/10=3x/5 persons ans.
  
  if x(population)=100
  Then persons travelling by car or bus will be 60 persons.
• 11 years agoHelpfull: Yes(28) No(5)
• If there are 100 persons,
  20 travel by car and 50 travel by bus.
  10 travel by both.
  so number of persons travelling by car or bus = 20+50-10 = 60
  so 60% travel by car or bus.
• 11 years agoHelpfull: Yes(26) No(0)
• p(car ∪ bus)=p(car)+p(bus)-p(car ∩ bus)
  Here given
  p(car)=20%.
  p(bus)=50%.
  p(car ∩bus)=10%.
  Putting the above value into formula we get p(carUbus)=60%.
  ans is person travelling with car or bus is 60%.
• 11 years agoHelpfull: Yes(6) No(0)
• n(car)=20
  n(bus)=50 n(car N bus)=10
  n(car U bus)=?
  AUB= A+B-AnB
  =20+50-10=60
• 11 years agoHelpfull: Yes(3) No(0)
• we knw that p(aub)=p(a)+p(b)-p(anb)-->1
  p(a)=people travel by car=20/100=1/5
  p(b)=people travell by bus=50/100=1/2
  p(aub)=people travel by both=10/100=1/10
  sub in 1
  1/10=1/5+1/2-p(anb)
  p(anb)=6/10=3/5
  so 60% travell by car or bus
• 11 years agoHelpfull: Yes(2) No(0)