The remainder when (15^23+23^23) is divided by 19 is
(1)4 (2)15 (3)0 (4)18

• (19-4)^23+(19+4)^23
  the remainder is 0.
  (19-4)^23 expansion all are multiplied by 19 except last term -4^23
  (19+4)^23 expansion all are multiplied by 19 except last term 4^23( as per principle of binomial theorem..............it is difficult to type)
  adding both we get 0
  
• 12 years agoHelpfull: Yes(5) No(0)
• (a^n+b^n) when divided by a+b leaves no remainder, if n is odd
  here also n=23(odd) so 15+23 will completely divide the sum nd so will 19
• 12 years agoHelpfull: Yes(4) No(0)