Q. The last digit of number is same as the last digit of its square. How many such a number exists from 0 to 90.

• Answer 37
  
  the only digits with square ending in same digits are 1,5,6,10
  
  therefore such numbers in one of these digits
  
  for eg 11,15,16,20 4 numbers between 11 to 20
  
  total numbers =9*4+1 (square of zero =0)=37
  
  
• 12 years agoHelpfull: Yes(9) No(0)
• ans=26... the numbers are 1,6,10,11,16,20,21,26,30,31.......86 (we will not take 90 because we are aked to write number between 0-90 )
• 12 years agoHelpfull: Yes(0) No(5)
• its 36,
  
  such numbers are 1,5,6 and 10
  so 1,11,21,31,41,51,61,71,81
  same with 5,6 and 10
  9*4=36
• 11 years agoHelpfull: Yes(0) No(0)
• answer is 37
  we have to find the last digit is same as the last digit of its square.
  so in 0 to 9 there are 4 numbers 0,1,5,6 whose last digit is same as square of that digit.
  so 10 to 19 there are also 4 no.
  like that 9*4=36 for 0 to 89
  and 90 also=1
  so total no will be 37
  
  
  
• 11 years agoHelpfull: Yes(0) No(0)