10.1 % of 9.6 % of x = an integer
then minimum possible positive integer value of x will be

• according to the given condition
  10.1/100 * 9.6/100 * x = I (Integer)
  on solving we get x = 250*125I/303
  so minimum positive value of x = 250*125 = 31250
  
• 11 years agoHelpfull: Yes(11) No(9)
• 31250 ans.
  sol:-
  10.1 % of 9.6 % of x = y(say)
  x = 100*100y/10.1*9.6=(100*100*100/9696)*y
  x = (25*25*50/303)*y=(31250/303)*y
  For only integer value of y=303 the minimum value of x will be possible
  hence,
  Minimum possible positive integer value of x = 31250 ans.
• 11 years agoHelpfull: Yes(8) No(5)
• (1/100)*(9.6/100)*x = I
  on solving
  
  X = [I*(10^5)]/ 96
  further
  x= (25*25*5*I)/3
  
  For x to be min and positive I should be the least positive multiple of 3 hence
  x = 25*25*5 = 3125
  
• 11 years agoHelpfull: Yes(3) No(0)
• ‎101/1000[96/1000(x)]=integer -----given
  for this, the value of x must cancel the denominator.....
  ans is 31250
• 11 years agoHelpfull: Yes(2) No(4)
• the minimum possible positive integer value of x will be 0
• 11 years agoHelpfull: Yes(0) No(7)
• (9.6/100)*(10.1/100)*x= integer. if we perform the division then (101*3)/(250*125)*x=integer. then x=125*250
• 10 years agoHelpfull: Yes(0) No(0)