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Maths Puzzle
32*(2^10)*1024 + 64*(2^13)*128 + 16*(2^18)*8 = ?
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- 32*(2^10)*1024 + 64*(2^13)*128 + 16*(2^18)*8 = 2^25 + 2^26 + 2^25
= 4*(2^25)
= 2^27
- 11 years agoHelpfull: Yes(4) No(4)
- 2^27 ans.
sol:-
32*(2^10)*1024 + 64*(2^13)*128 + 16*(2^18)*8
=2^(5+10+10) + 2^(6+13+7) + 2^(4+18+3)
=2^25 + 2^26 + 2^25
=(1+2+1)2^25=2^(2+25) = 2^27 ans. - 11 years agoHelpfull: Yes(2) No(3)
- 101/1000[96/1000(x)]=integer -----given
for this, the value of x must cancel the denominator
so ans is 31250 - 11 years agoHelpfull: Yes(0) No(3)
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