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Maths Puzzle
The sum of n terms of two arithematic progressions are in the ratio (3n+8):(7n+15) the ratio of 12th term are
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- put n=2*12-1=23
so the ratio of 12th term = (3*23+8):(7*23+15)=77:176=7:16 - 12 years agoHelpfull: Yes(0) No(1)
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