A die is rolled twice. What is the probability of getting a sum equal to 9?

Options
A. 2/3
B. 2/9
C. 1/3
D. 1/9

• total pair 6*6 = 36
  and pair whose sum is = 9 i.e= (6,3), (3,6) ,(5,4) and (4,5)
  so probability of getting sum equal to 9 = 4/36= 1/9
• 9 years agoHelpfull: Yes(16) No(0)
• 1/9
  ek bar ki baat h
  ek batta no to phr uski foki tut gyi
• 9 years agoHelpfull: Yes(2) No(1)
• Total number of outcomes possible when a die is rolled = 6 (∵ any one face out of the 6 faces)
  
  Hence, total number of outcomes possible when a die is rolled twice, n(S) = 6 × 6 = 36
  
  E = Getting a sum of 9 when the two dice fall = {(3, 6), {4, 5}, {5, 4}, (6, 3)}
  
  Hence, n(E) = 4
  
  P(E) =n(E)/n(S) =4/36=1/9
• 7 years agoHelpfull: Yes(1) No(0)
• d) 1/9
  
  no of favorable event is {(3,6),(6,3),(4,5),(5,4)}=4
  no of total event =36
  so probability=4/36=1/9
• 9 years agoHelpfull: Yes(0) No(0)
• d)1/9
  There is four chances (3,6),(6,3),(5,4) and (4,5)
  prob=4/36
• 9 years agoHelpfull: Yes(0) No(0)
• 1/9 is the ans
• 9 years agoHelpfull: Yes(0) No(0)
• No of ways of getting the sum 9 from 2 pairs of dice is 4 times.
  Total no of combinations from 2 pairs of dice is 36.
  Hence the probability is 4/36 = 1/9
• 8 years agoHelpfull: Yes(0) No(0)
• Total possibilities:36
  Possibilities of sum eq to 9 :4--->{(3,6),(4,5),(5,4),(6,3)}
  prob=4/36=1/9
• 8 years agoHelpfull: Yes(0) No(0)
• ans= 1/9
  total cases= 6*6=36
  sum equal to 9= {(3,6), (6,3), (4,5), (5,4)}=4
  probabillity= 4/36
  =1/9
• 7 years agoHelpfull: Yes(0) No(0)
• D. 1/9
  sample space(3,6)(6,3)(4,5)(5,4) for two outcomes
• 7 years agoHelpfull: Yes(0) No(0)
• answer is 1/9
• 7 years agoHelpfull: Yes(0) No(0)
• 4/6=2/3
  Because one die
• 7 years agoHelpfull: Yes(0) No(2)
• Time saving trick ---> when 2 dices are thrown and sum is ask then use this rule
  if sum is upto 7 then subtract -1 into sum
  if sum is greater than 7 then do 13-sum
  eg In above question 13-9=4
  4/36=1/9
  eg
  if sum is 5 then 6-1=5
  5/36
  this valid for only 2 dices
• 6 years agoHelpfull: Yes(0) No(0)
• 4,5 and 5,4 and 6,3 and 3,6 over 36 assumptions hence 4/36
• 5 years agoHelpfull: Yes(0) No(0)
• two die 6^2=36
  sum of observation=(3,6),(6,3),(4,5),(5,4) = 4
  probability = sum of observation/possibility
  probability = 4/36 = 1/9
• 5 years agoHelpfull: Yes(0) No(0)
• 4/36 = 1/9 Option D
• 3 years agoHelpfull: Yes(0) No(0)