Seven different objects must be divided among three people. In how many ways can this be done if atleast one of them must gets exactly 1 object ?a> 2484b> 1176c> 729d> 2424e> None

• In 1176 ways ,if atleast one of them must gets exactly 1 object.
• 11 years agoHelpfull: Yes(6) No(7)
• Ans:- None of these
  You can verify my answer from Arun Sharma book
  by clicking here
  http://linkshrink.net/7jOvac
  
  One of them get no object.
  So it may be distributed as:-
  
  1. when one of them get no object
  0,1,6
  Total ways= (7C0x7C1x6C6)3!=42
  or
  0,2,5
  Total ways= (7C0x7C2x5C5)3!=126
  or
  0,3,4
  Total ways= (7C0x7C3x4C4)3!=210
  
  total ways
  42+126+210=378
  
  
  
  
• 8 years agoHelpfull: Yes(1) No(1)