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Numerical Ability
Arithmetic
If a,b,c be in GP and p,q be respectively AM between a,b and b,c then
(a) 2/b=1/p+1/q
(b) 2/b=1/p-1/q
(c) 2=a/p-c/q
(d) None of the above
Read Solution (Total 2)
-
- Option (a)
p=(a+b)/2; q=(b+c)/2
1/p+1/q = 2*((1/(a+b))+(1/(b+c))
= 2*(a+2b+c)/(a+b)(b+c)
= 2*(a+2ar+a(r^2))/(a+ar)(ar+a(r^2)) because b=ar; c= a(r^2)
where r - common ratio
On simplication
1/p+1/q = 2/ar = 2/b
- 12 years agoHelpfull: Yes(9) No(3)
- Ans:d
Assume a,b,c=2,4,8
p,q=2,4 then none of a or b or c satisfied. - 12 years agoHelpfull: Yes(2) No(2)
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