Huawei
Company
Numerical Ability
Algebra
Q. A ladder was rested along a wall of height 5m. If ladder slides 2m away from the wall then ladder touches the foot of the wall .What is the height of the ladder.
Read Solution (Total 5)
-
- suppose , earlier foot of ladder was x mtres away from wall, then
length of ladder = x+2 mtrs
hence
(x+2)^2 = x^2+5^2
x= 21/4 = 5.25 mtrs
length of ladder = 5.25+2= 7.25 mtrs - 12 years agoHelpfull: Yes(35) No(7)
- ladder is rested along the wall then if ladder touches the foot of the wall by sliding 2m away it must be length of ladder be 2m.
so answer must be 2m. - 11 years agoHelpfull: Yes(8) No(7)
- suppose wall is at right angle then ladder will slide that is the hypotenuse of a triangle therefore length of ladder =root of (5^2+2^2)=root of(29)...is this correct or not
- 10 years agoHelpfull: Yes(7) No(2)
- height of wall=5
let dis frm wall of ladder=x
then ladder length=x^2+5^2..................(1)
when ladder slide ,base becomes=x+2
then ladder length=(x+2)^2..................(2)height of wall becomes 0;
by equating 1 &2 we get x=5.25 (that is base)
now height of ladder is=2+5.25=7.25 - 9 years agoHelpfull: Yes(1) No(1)
- Let before moving , base was x
So after moving 2m the foot of the wall ,so length will be x+2
Taking base = x perpendicular is x+2 and height 5
Apply Pythagoras
X^2 +5^2= (x+2)^2 - 10 years agoHelpfull: Yes(0) No(1)
Huawei Other Question