Q) if 764xy is divisible by 90 then x+y=

a)1
b)3
c)5
d)6

• a) 1
  For a number to be divisible by 90 it must be divisible by 9 & 10 both
  So for a given number 764xy , y=0 & 764x should be divisible by 9 so x=1
  hence x+y=1+0=1
• 9 years agoHelpfull: Yes(7) No(1)
• option "a" is the correct answer.
  since the no 764xy is divisible by 90
  hence the the given no is must be divisible by 3,9 and 10.
  to perfectly divisible by 3 and 9 it should be necessary to the sum of all digit must be divisible by 3 or 9,and it is also necessary that the last digit is zero becoz the no should be also divisible by 10.
  
  hence,
  7+6+4+x+y
  where y=0
  so 7+6+4+x+0
  if x=1 then sum= 18 which is divisible by 3 as well as 9
  
  so (x+y)=1
• 9 years agoHelpfull: Yes(2) No(0)
• 1 because 1+0
• 9 years agoHelpfull: Yes(1) No(1)
• To make 764xy divisible by 90 ,the number has to be divisible by 9 and 10.
  Divisibility rule of 10: last digit should be 0. Hence y=0.
  Divisibility rule of 9: sum of all digits should be divisible by 9. Hence 7+6+4+x+0 should be divisible by 9.
  We get 17+x from the addition . And to make it divisible by 9 ,x=1 suck that 17+1=18 is divisible by 9.
  Therefor x+y=1+0=1.
• 6 years agoHelpfull: Yes(1) No(0)
• 7+6+4+x+y=90
  17+x+y=90
  x+y=73
• 9 years agoHelpfull: Yes(0) No(5)