Huawei
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Numerical Ability
Algebra
Q. Average of 9 numbers is m,avg of 3 nos is n avg of rest of the nos is p,what is the equation formed?
Read Solution (Total 8)
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- Average of 9 numbers is m,
total of 9 numbers = 9m
avg of 3 nos is n
total of 3 numbers = 3n
total of balance 6 numbers = 9m-3n
avg of balance 6 numbers = (9m-3n)/6
so reqd en is
p= (9m-3n)/6 - 11 years agoHelpfull: Yes(18) No(1)
- Average of 9 numbers is m
sum of 9 numbers is 9m
Average of 3 numbers is n
sum of 3 numbers is 3n
Average of rest 6 numbere is P
Sum of rest 6 numbere is 6P
now ,
Sum of 9 numbers =sum of 3 numbers +sum of 6 numbers
9m=3n+6P
- 11 years agoHelpfull: Yes(8) No(0)
- avg of 9 nos=m
total=9m
avg of 3 nos. is=n
total=3n
rest i.e.(9-3)=6 nos. avg=p
total=6p
rd eqn is, 9m=3n+6p
i.e.,3m=n+2p - 11 years agoHelpfull: Yes(4) No(0)
- p= (9m-3n)/6
- 11 years agoHelpfull: Yes(2) No(0)
- P=(9m-3n)/6
- 11 years agoHelpfull: Yes(1) No(0)
- 9m=3n+6p..
- 10 years agoHelpfull: Yes(1) No(0)
- 3n+6p=9m
- 10 years agoHelpfull: Yes(1) No(0)
- avg of 9 number=9m,
avg of 3 number=3n,
avg of 6 number=6p,
equating these all equation,
9m=3n+6p
3m=n+2p - 9 years agoHelpfull: Yes(1) No(0)
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