Let b be an odd square and n be any natural number. Then b=n^3+2n^2. Find b?
A)81
B)49
C)441
D)9
E)None

• 441
  
  441 = 7^3 +2*7*7= 343+98=441= 21^2
• 12 years agoHelpfull: Yes(4) No(1)
• C) 441
  441=21^2
  b = n^3+2n^2
  = 7^3+2(7)^2
  = 343+2(49)
  = 343+98
  = 441
• 12 years agoHelpfull: Yes(2) No(1)
• ans is b=441 where n=7
  by checking n for different values we can get the ans
• 12 years agoHelpfull: Yes(1) No(0)