The square of three consecutive numbers is 365.Find out smallest number?

• No need to solve your own question and if
  you will mentioned -12,-11,-10 three consecutive numbers then you will get the same R.H.S.
  So plz check...
• 11 years agoHelpfull: Yes(2) No(1)
• let three nos are 10,11,12
  10^2+11^2+12^2=365
  100+121+144=365
  smallest number=10
• 11 years agoHelpfull: Yes(0) No(2)
• @jaya mishra,
  No need of ans your own question.
• 11 years agoHelpfull: Yes(0) No(1)
• let three cosecutive numbers are : (x-1),x,(x+1)
  now,
  (x-1)^2+x^2+(x+1)^2=365
  x^2-2x+1+x^2+x^2+2x+1=365
  3x^2+2=365
  x^2=(365-2)/3
  x=11
  therefore, the numbers are: 10, 11 , 12
  smallest number is: 10 ans
• 11 years agoHelpfull: Yes(0) No(2)
• Three consecutive numbers are a-1,a,a+1.
  Sum of the squares of 3 consecutive number is (a-1)^2+a^2+(a+1)^2 = 365
  a^2-2a+1+a^2+a^2+2a+1 = 365
  3a^2+2 = 365
  3a^2 = 363
  a^2 = 121
  a = +11 or -11
  The consecutive numbers are,-12,-11,-10 & 10,11,12
  the smallest number is -12.
• 11 years agoHelpfull: Yes(0) No(1)