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Numerical Ability
Age Problem
A man is 37 yrs old and his two sons are 8 yrs and 3 yrs old. After how many years will he be twice as old as sum of the ages of his sons?
Read Solution (Total 10)
-
- let x be d no of yrs...
37+x=2(8+3+2x)
so x=5 - 12 years agoHelpfull: Yes(17) No(0)
- Ans: 5
Let the ans be x, then
after x years,
2*(8+x +3+x) = 37+x
22+4x = 37+x
3x = 15
x = 5 - 12 years agoHelpfull: Yes(11) No(0)
- After 5 years
37+5=42
(8+5)+(3+5)=13+8=21
21*2=42 - 12 years agoHelpfull: Yes(4) No(2)
- afther 5 year
- 12 years agoHelpfull: Yes(3) No(0)
- 5
37+x=2[(8+x)+(3+x)]
22+4x-x=37
3x=15
x=5 - 12 years agoHelpfull: Yes(3) No(0)
- after 5 years
- 12 years agoHelpfull: Yes(2) No(0)
- let the year is = x
then
37+x=2(11+2x)
then x=5
ans x=5 - 12 years agoHelpfull: Yes(1) No(0)
- 37+y=2(11+y) so after 15 years is the answer
- 9 years agoHelpfull: Yes(0) No(0)
- m=37
s1=8
s2=3
37+t=2{(8+t+3+t)}
15=3t
t=5 - 9 years agoHelpfull: Yes(0) No(0)
- 37+x=2((8+x)+(3+x))
37+x=22+4x
x=5 - 9 years agoHelpfull: Yes(0) No(0)
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