By using 1,2,3,4,5,how many 5 digit number can be formed which is divisible by 4 and repitition of the number is allowed?

• 12,24,32,44,52 are 5 possibilties ..
  
  5 * 5 * 5 three digits and 5 for last two digits
  
  625!!
• 12 years agoHelpfull: Yes(20) No(4)
• the number divisible by 4 is only 4
  so unit place can be filled in one way,and in other cases repetition is allowed ,so the combination will be
  5*5*5*5*1=625 ans
• 12 years agoHelpfull: Yes(6) No(10)
• formula is 5^n-1=5^5-1=5^4=625
• 12 years agoHelpfull: Yes(6) No(1)
• ans is 500...
  no. is divisible by 4 when last two digits are divisible by 4
  _ _ _ 1 2 (5*5*5)= 125
  _ _ _ 2 4 .
  _ _ _ 3 2 .
  _ _ _ 5 2 .
  =125* 4 =500
• 12 years agoHelpfull: Yes(5) No(7)
• just check the divisibility condition of in the last two digit of the 5-digit no. we will get (12,24,32,44,52) as combinations and rest as repetition is allowed 5*5*5*5=625
• 12 years agoHelpfull: Yes(3) No(1)
• 24 32 52 12 are divisible by 4 so digit in unit n ten place should b 24 or 32 or 52 or 12.. so ans is 5*5*5*4=500
• 12 years agoHelpfull: Yes(2) No(2)
• the number is divisible by 4 is 24 and 42
  so unit place can filled in 2 ways(either 2 or 4 can come)
  tenth place can filled in 2 ways(either 2 or 4 can come)
  and other three digit can be filled by 5 ways each,because repetiton is allowed
  so the combination will be
  5*5*5*2*2=500 ans
  
  
  
  
  
  
• 12 years agoHelpfull: Yes(2) No(5)
• formula : 5^(N-1)
  5^4
• 12 years agoHelpfull: Yes(2) No(1)
• ans =250.
  There are two no .24 and 32 which is divided by 4 . means the possibility to place value at end two place is 2. and repitition of number allowed so that the total cases at first 3 place are
  5*5*5 =125
  now the total number is 125*2=250
• 12 years agoHelpfull: Yes(1) No(6)
• 5*5*5*5*2=1250
  because at unit's place only 2&4 can come while at other places any of the 5 digits can come
• 12 years agoHelpfull: Yes(1) No(5)
• 2250...9*10*10*25..
• 12 years agoHelpfull: Yes(1) No(2)