Two people agree to meet on January 9, 2005 between 6.00 P.M. to 7.00 P.M., with the understanding that each will wait no longer than 20 minutes for the other. What
is the probability that they will meet ?

• Probability of 1st people, P(A)=20/60=1/3
  Probability of 2nd people, P(B)=20/60=1/3
  
  P(AUB)=P(A)+P(B)-P(A)*P(B)
  =1/3+1/3-1/9
  =5/9
• 11 years agoHelpfull: Yes(59) No(8)
• Let A,B be two persons
  Probability of A P(A)=20/60=1/3;
  Probability of B P(B)=20/60=1/3;
  Probability A and B so that they will not meet is (1/3*2/3)+(1/3*2/3)=4/9
  According to question probability of A and B they will meet is 1-4/9=5/9
• 10 years agoHelpfull: Yes(13) No(1)
• probability that they will meet = 5/9
  
  I shall submit detailed calculation later.
• 11 years agoHelpfull: Yes(7) No(24)
• they can meet with each other that is 38 times possible and total time is 60
  
  38/60 ===== 19/30
• 11 years agoHelpfull: Yes(1) No(24)
• They can meet when A comes between 6: 00 = 6: 40.
  
  And so B can join him between 6: 20 = 7: 00.
  
  Similarly, the process can be reversed.
  
  Therefore p=(40 / 60)2 = 4/9.
• 5 years agoHelpfull: Yes(0) No(0)