in a chimpoo zoo there are 1 billion monkeys..the probability that a monkey in the zoo has seen a banyan tree is 0.6.the prob that a monkey has seen a mango treee is 0.65.wat is the minimum % of monkeys in the zoo who have seen both the trees??

• only 0.6 monkeys can see banyan trees so 0.4monkeys can not see banyan trees...(1)
  
  now we can see that only 0.65monkeys can see mango trees so to find minimum monkeys that can see both trees are 0.65-0.4==0.25
• 11 years agoHelpfull: Yes(11) No(2)
• the minimum % of monkeys in the zoo who have seen both the trees = 100*0.65*0.6 = 39%
• 11 years agoHelpfull: Yes(1) No(7)
• Mr the nalesh can you please explain me the logic u have used
• 7 years agoHelpfull: Yes(0) No(0)
• P(A AND B)=P(A)*P(B)
  P(monkeys who have seen both)=0.6*0.65=0.39
  % of monkeys who have seen both= 0.39*100=39%
• 6 years agoHelpfull: Yes(0) No(0)