MRW
BSM
HSGA
ARYBX
RRHYXX
RBHYBA

• 
  743
  627
  ---------
• 9 years agoHelpfull: Yes(4) No(0)
• How can u get that the value of R ?
• 9 years agoHelpfull: Yes(3) No(0)
• 743
  627
  --------
  5201
  1486
  4458
  ---------
  465861
• 9 years agoHelpfull: Yes(2) No(1)
• MRW
  * BSM
  -------------------
  HSGA
  AR Y B
  R R H Y
  ----------------------
  R B H Y B A
  
  
  In this problem the only fst clue we can get is R can be less than 5
  
  so ill start my procedure with R=4
  
  now from MRW *B= RRYH
  
  => M4W* B= 44YH
  
  now we have to get 44 as fst two digits in 44YH
  to get this we have to take M and B values which when multiplied should give nearest value to 44
  so when M=7 and B=6 or B=7 and M=7 it wil satisfy
  
  so ill start with M=7 and B=6
  
  now
  => 74W* 6 = 44HY
  
  and from second column i.e A+R+carry= B
  we can have carry as only1
  
  A+4+1=6
  so we get A=1
  
  and now from third column we have H+H+R+carry=H
  
  =>H+H+4+1=H
  H+H+5=H
  we will satisfy this equation with H=5
  so we got H=5 now
  
  now from MRW* B= RRHY
  
  => 74W* 6=445Y
  
  and from MRW* M= HSGA
  from 5th column we have that G+B=B
  G+6=6 , from this we got G=0
  
  74W*7= 5S01
  
  to get last digit as 1 we have to take W=3
  
  so => 743*7= 5201
  
  so ,S=2
  
  and now from MRW*S= ARYB
  => 743*2= 1486
  => from this mwe get Y=8
  
  i think i got this
  
  743*
  627
  
  ----------
  5201
  1486
  4458
  ----------------
  4 6 5 8 6 1
• 9 years agoHelpfull: Yes(2) No(0)
• bro u typed wrong
• 9 years agoHelpfull: Yes(0) No(1)
• kha error h bhai btaooo
• 9 years agoHelpfull: Yes(0) No(0)
• 7 4 3
  6 5 2
  5 2 0 1
  1 4 8 6
  4 4 5 8
  4 6 5 8 6 1
• 8 years agoHelpfull: Yes(0) No(0)
• How can be R = 4?
• 8 years agoHelpfull: Yes(0) No(0)