A train crosses a platform 100meter long in 60seconds at a speed of 45kmph the time taken by the train to cross an electric pole is
a.8sec b.52s c.1minute d.data inadequate

• 52 secs
  
  Distance travelled by train in 60 secs = 60*45*5/18 = 750 mtrs
  length of train = 750-100= 650 mtrs
  time taken by 650 mtr train to cross pole = 650*18/(45*5)= 52 secs
• 11 years agoHelpfull: Yes(9) No(0)
• 60=(100+L)/(25/2)
  L=650
  T=650/25/2 =26*2=52s
• 11 years agoHelpfull: Yes(2) No(0)
• 60=(100+l)/45*5/18
  l=650
  so
  t=650/[45*(5/18)]
  t=52sec
  
• 9 years agoHelpfull: Yes(0) No(0)
• definately 52 sec yar it takes equal time to cross a man as its speed
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• 60=(100+L)/(25/2)
  L=650
  T=650/25/2 =26*2=52s
• 9 years agoHelpfull: Yes(0) No(0)
• 45 kmph =45*5/18 m/sec
  45*5/18 =100+l/60
  100+l = 750 metre
  l =650 metre = length of the train.
  now
  time required to cross an electric pole
  45* 5/18= l/t
  45*5/18= 650/t
  t= 52 secs
• 9 years agoHelpfull: Yes(0) No(0)
• 52 sec is the ans
• 9 years agoHelpfull: Yes(0) No(0)