A train runs first half of the distance at 40km/hr. and the remaining half at 60 km/hr.what is the average speed for the entire journey?

• Average Speed=(2*40*60)/(40+60)=48 km/hr.
• 12 years agoHelpfull: Yes(40) No(2)
• 48 KM/HR
  
  40 t1 = 60 t2
  
  t1/t2 =3/2
  
  total distance = 120+120 =240 ,time taken 5 hrs
  
  average speed =240/5=48
  
  anthor method
  
  average speed =2ab/a+b = 2*40*60/(40+60) = 48
• 12 years agoHelpfull: Yes(20) No(3)
• 48km/hr
  solution:
  the average speed is:(2*40*60)/(40+60)
  48
• 12 years agoHelpfull: Yes(8) No(2)
• 48km/hr
  let total distance=2x
  avg speed=2x/(x/40+x/60)=48 km/hr
• 12 years agoHelpfull: Yes(7) No(1)
• first half journey speed X=40
  and second half journey speed is Y=60
  then for average speed =(2*X*Y)/(X+Y)
  so ans is 48kmph
• 12 years agoHelpfull: Yes(6) No(1)
• speed= distance/time
  speed=(40+60)/2
  =50
  there fore avg speed is 50km/hr
• 12 years agoHelpfull: Yes(4) No(38)
• 48 km/hr
  using the formula 2*x*y/x+y
• 11 years agoHelpfull: Yes(0) No(0)
• avg speed= (2*40*60)/40+60
  
  ans is 48km/hr
• 11 years agoHelpfull: Yes(0) No(0)
• average speed=2*x*y/x+y
  so 2*60*40/60+40
  480/100=48km/h
• 9 years agoHelpfull: Yes(0) No(0)
• (2*40*60)/(40+60)=(2*40*60)/100=48km/hr
• 7 years agoHelpfull: Yes(0) No(0)