How many factors of 1800 are perfect square ?
A)4 B)5 C)6 D)7

• Ans is d)7
  factors of 1800 which are perfect square:4,9,25,36,100,225,900.
• 12 years agoHelpfull: Yes(6) No(0)
• look 1800 can be broken as 2^3 3^2 5^2
  nw the combinations of perfect square that can be made is 2^2 , 3^2, 5^2 , 2^2*3^2 ,2^2*5^2 , 3^2*5^2 , 2^2*3^2*5^2.............tats all 7 combination soo the ans is 7....
  
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• Ans. D)7.
  
  The required factors are 4, 9, 25, 36, 100, 225, 900
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• D)7
  4,25,9,10,15,6,30
• 12 years agoHelpfull: Yes(1) No(1)
• Ans:(d)
  [2^0+2^1+2^2+2^3]*[3^0+3^1+3^2]*[5^0+5^1+5^2]
  from above expression we get factors:4,25,36,100,225,900.
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• ans is 7
  factors of 1800 which are perfect square are 4,9,25,36,100,225,900
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• solution is 8 coz 1,4,9,25,36,100,225,900
• 12 years agoHelpfull: Yes(1) No(1)
• 1800=3^2 * 5^2 * 2^3
  factors which are perfect sq are 4, 25, 9, 100, 225,36, 900
• 12 years agoHelpfull: Yes(1) No(0)
• 1800 = 2^3 * 5^2 * 3^2;
  =(floor(3/2)+1)(floor(2/2)+1)(floor(2/2)+1)(in 3/2 3 is pow f 1st prime factor)
  = (1+1)*(1+1)*(1+1)-1(subtracting to avoid taking 1 as factor)
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• solution b) 5
  possible perfect squares of 1800 are 4,9, 25 ,36, 100
• 12 years agoHelpfull: Yes(0) No(7)