The size of program is N.And the memory occupied by the program is given by M=square root of 100N.If the size of the program is increased by 1% then how much more memory is required now?
a.1.0%
b.2.6%
c.0.5%
d.1.4%

• Initially size=N, memory=100N
  size increased by 1%, means new size=1.01N, new memory=100*1.01N=101N
  Percentage increase in memory=1%
  Ans= 1%
• 12 years agoHelpfull: Yes(14) No(3)
• size memory(M)
  n (100n)^0.5=10sqrt(n)
  1.01n 10sqrt(1.01n)=1.0049*10sqrt(n)=1.005M
  difference in memory=0.005M
  %increase in memory=(0.005M/M)*100=0.5%
• 12 years agoHelpfull: Yes(10) No(1)
• abe gadho saab galat ho tum iska answer 0.5 hai
  
• 12 years agoHelpfull: Yes(6) No(11)
• when program size=N;
  Memory M=(100N)^(1/2); //square root of 100N from Question
  size of increase 1%, M=(100*1.1)^(1/2) = (110)^(1/2);
  (100)^(1/2)=10;//at N Memory
  (100*1.1)^(1/2)=10.4; //at N=1% increase
  required Memory increase = 4% (note-none of the options is correct)
• 12 years agoHelpfull: Yes(3) No(5)
• CAN ANY ONE EXPLAIN IT PLZ?!
• 12 years agoHelpfull: Yes(1) No(7)
• Given that program size=n
  Memory Size= square root(10n)
  because program size is increased by 1%
  so now size will be = n+n/100;
  =101n/100
  now the memory size wil be= square root of 101n/100;
  more memory required in %= (10.05-10)*100/10=0.5%
  so 0.5 will be the right ans
• 8 years agoHelpfull: Yes(1) No(0)
• Initially size=N, memory=100N
  size increased by 1%, means new size=1.1N, new memory=100*1.1N=110N
  Percentage increase in memory=10%
  Ans= 10% (note-none of the options is correct.)
• 12 years agoHelpfull: Yes(0) No(5)
• Initial size= N , memory= 100N
  size increased = 1% ,so total size= N+(N/100)=101N/100,
  so memory increased m= square root of (100*(101N/100)=1%
  so answere = 1%
• 12 years agoHelpfull: Yes(0) No(2)