A hare and a jackal are running a race.Three leaps of the hare are equal to four leaps of the jackal. For every six leaps of the hare,the jackal takes 5 leaps.Find the ratio of their speeds.

• Let 1 leap of hare=x and 1 leap of jackal=y;
  Then 3x=4y => (x/y)=(3/4);
  For every 6 leaps of hare, the jackal takes 5 leaps, this implies when hare covers distance of 6x, jackal covers 5y so ratio of there speeds is (6x/5y)=(6/5)*(3/4)=(9/10)
  Ans=(9/10)
  
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