There are 200 numbers from 1 to 200.what is the probability of getting the number which is divisible by either 2 or 3 or 5?

• Ans: 73/100
  Lets take numbers 1 to 30
  numbers which are not divisible by 2,3,5 = 1,7,11,13,17,19,23,29
  there are 8 numbers b/w 1 to 30.
  1 to 30 is similar to 30 to 60, 60 to 90...so on
  so for 1 to 180 it will be 8*6=48
  from 180 to 200 its 6 numbers.
  Total from 1 to 200 numbers not divisible by 2,3,5 are 54.
  So from 1 to 200 numbers divisible are 200-54=146.
  therefore probability is 146/200 = 73/100
• 12 years agoHelpfull: Yes(1) No(1)
• numbers divisible by 2=100
  3=66
  5=40
  0f 100 numbers divisible by 2,20 divisible by 5 and 33 divisible by 3
  ===>numbers divisble only by 2=47
  
  0f other 33 numbers divisible by 3,7 divisible by 5
  ===>numbers divisble only by3=7
  
  ===>numbers divisible only by 5=40-7-20=13
  
  so numbers divisible either by 2 or 3 or 5=13+7+47=67
  
  so probabilty=67/200
• 12 years agoHelpfull: Yes(0) No(2)
• 18/25
  206 numbers are divisible by each of 2,3 and 5.
  68 are divisible by two of them
  6 are divisible by all 3
  venn diagram logic -> 206-68+6=144
  ergo, probability=144/200=18/25
• 12 years agoHelpfull: Yes(0) No(1)