Elitmus
Exam
Numerical Ability
Number System
Below a sequence of number is given, fill the blank space
1) 6, 5, 43.2
2) 5, 4, 31.25
3) 4, 3, 21.33
4) 3, 2, .....
Read Solution (Total 14)
-
- 6^3=216/5=43.2
5^3=125/4=31.25
4^3=64/4=21.33
So 3^3=27/2=13.5 - 9 years agoHelpfull: Yes(36) No(0)
- 6, 5, 43.20
(6)^2 - (5)^2 = 11 and 43.20 - 11 = 32.20 and 32.20 - 31.25 = 0.95
(5)^2 - (4)^2 = 9 and 31.25 - 9 = 22.25 and 22.25 - 21.33 = 0.92
(4)^2 - (3)^2 = 7 and 21.33 - 7 = 14.33 and 14.33 - 0.89 = 13.44
Since the difference is 0.95, 0.92....0.89
Hence 13.44 is the answer according to series - 9 years agoHelpfull: Yes(18) No(6)
- I think it shud be 13.44 as per the given series... what are the options
- 9 years agoHelpfull: Yes(12) No(6)
- i think answer will be 13.5.... options?
- 9 years agoHelpfull: Yes(7) No(1)
- Let the pattern be : a , b , c
c = a * (a+1) + a/b
43.2 : 6*7 + 6/5
31.25 = 5*6 + 5/4
21.33 = 4*5 + 4/3
Ans is 13.5 ( 3*4 + 3/2)
- 9 years agoHelpfull: Yes(4) No(0)
- 43.2 - 31.25=11.95
31.25 -21.33=9.92
21.33 - ? =7.89
?=13.44 - 9 years agoHelpfull: Yes(2) No(1)
- 3/2=1.5 , take 0.5
3*2+7=13
hence, ans is 13.5 - 9 years agoHelpfull: Yes(1) No(0)
- 6*7(next Number)+6/5->42+1.2=43.2
5*6+5/4->30+1.25=31.25
4*5+4/3->20+1.33=21.33
3*4+3/2->12+1.5=13.5
So 13.5 may be the answer - 9 years agoHelpfull: Yes(1) No(0)
- 6, 5, {(7*6)+(6/5)}=43.2
5, 4, {(6*5)+(5/4)}=31.25
4, 3, {(5*4)+(4/3)}=21.33
3, 2, {(4*3)+(3/2)}=13.5 ....ans - 9 years agoHelpfull: Yes(1) No(0)
- Ans : 3*2+(3+2)+(3/2)+(3-2)=13.5
- 9 years agoHelpfull: Yes(1) No(0)
- yes your answer is right
- 9 years agoHelpfull: Yes(0) No(2)
- 6*7=42. 6รท5=1.5
42+1.5=43.5
Same for remaining - 9 years agoHelpfull: Yes(0) No(0)
- It is....
(6*7+1)=43
(5*6+1)=31
(4*5+1)=21
(3*4+1)=13....so 13 is the answer - 9 years agoHelpfull: Yes(0) No(0)
- here option is not given so i think
1st method:
6^3=216
216/5=43.2
2=5^3=125
125/4=31.25
3 . 4^3=64
64/3=21.33
4. 3^3=27
27/2= 13.5
- 8 years agoHelpfull: Yes(0) No(0)
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