3 circles of 1 m radius touches externally,what is the area in between those circles?

• Reqd area= (area of equilateral triangle with side 2m)- 3*( area of sector having angle of 60 deg at centre of circle of radius 1 m)
  = (((Root3)/4)*2^2)- 3*Pi*1/6 = root 3 - pi/2= 1.73 - 1.57 = 0.16 sq mtr
• 12 years agoHelpfull: Yes(4) No(0)
• ans:.162sqr m.
  area of equilateral triangle of side 2 = a1 = sqrt(3)/4*(2)^2
  area of sectors = a2 = 3*Pi*1^2/6 =
  required area = a1-a2=ans
• 12 years agoHelpfull: Yes(0) No(1)