an alloy of gold silver and bronze contains 90% bronze 7% gold and 3% silver A second alloy of bronze and silver only is melted with the first and the mixture contains 85% of bronze 5% of gold and 10% of silver Find the percentage of bronze in the second

• 7% gold + 0% gold = 5% gold...
  that means ration of mixing done is 5:2 ( solve it using allegations and mixture)
  
  therefore, 90% bronze + x% bronze = 85% bronze
  keeping ratio 5: 2 clearly the answer is 72.5%
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