There are 19 red balls and one black ball. Ten balls are put in one jar and the remaining 10 are put in another jar. What is the possibility that the black is in the right jar.

• the possibility that the black is in the right jar = 1/2
• 12 years agoHelpfull: Yes(6) No(1)
• the probability of getting a black ball is --->> 1-probabilty of all red balls
  so
  1-[19C10/20C10)]
  1-[1/2]
  =1/2
  
• 12 years agoHelpfull: Yes(5) No(0)
• The probability that the Black ball is in the first jar
  = 19C9 / 20C10 = 1/2.
• 12 years agoHelpfull: Yes(0) No(1)
• how cum 19C9 wil b the prob of blackbals...plz xpln
• 12 years agoHelpfull: Yes(0) No(0)
• probablity=19C9/20C10
• 6 years agoHelpfull: Yes(0) No(0)