What is the value of (78*78*78-45*45*45)/(78*78+78*45+45*45)

• (a^3-b^3)=(a-b)(a^2+ab+b^2)
  here put a=78 and b=45
  we have to find a-b
  that is answer is 33
• 13 years agoHelpfull: Yes(14) No(1)
• 78-45=33
• 13 years agoHelpfull: Yes(2) No(1)
• The prob. is of the type (a^3-b^3)/(a^2+ab+b^2)=a-b
  So, ans. is 78-45=33
• 13 years agoHelpfull: Yes(2) No(0)
• (a*a*a-b*b*b)/(a*a+a*b+b*b)= a-b
  thus, answer is (78-45)=33
• 13 years agoHelpfull: Yes(1) No(0)
• 78-45
• 13 years agoHelpfull: Yes(0) No(0)
• 78-45=33
• 13 years agoHelpfull: Yes(0) No(0)
• try this formula.
  a3-b3=(a+b) (a2-ab+b2)
• 13 years agoHelpfull: Yes(0) No(1)
• 78-45=33
• 13 years agoHelpfull: Yes(0) No(0)
• 33
• 13 years agoHelpfull: Yes(0) No(0)
• Answer is 33;
  (a^3-b^3)/(a^2+ab+b^2)=(a-b)(a^2+ab+b^2)/(a^2+ab+b^2)
  =a-b;
  =78-45=33
• 9 years agoHelpfull: Yes(0) No(0)