Peter and Paul Are two friends.The sum of their age is 35.Peter is twice as old as Paul was when Peter was old as Paul is now.What is the present age of Peter?

• let age of peter is pe and paul is pa.
  peter was as old as paul is now X year before.
  pe-X=pa---1
  then
  pe=2(pa-X)---2
  pa+pe=35---3
  after solved 1,2,3
  pe=20
  pa=15
• 12 years agoHelpfull: Yes(5) No(2)
• for this questions just use formule 7x/4 = sum of ages,
  
  then 7x/4=35 => x=20
• 12 years agoHelpfull: Yes(3) No(1)
• peter paul
  x y
  y x/2
  now age difference-x-y=y-x/2
  x+y=35
  x=20
  y=15
  
• 12 years agoHelpfull: Yes(2) No(1)
• |
  | Peter Paul
  --------------|-------------------------------------
  Present age | 2x 35-2x
  --------------|-------------------------------------
  Past age | 35-2x x
  
  diff of Peter ages = diff of paul ages
  
  2x-(35-2x) = (35-2x)-x
  .
  . . x = 10
  From the table present age of peter= 2x=2*10 =20 yrs
• 12 years agoHelpfull: Yes(1) No(1)
• suppose paul is x years old
  now when Peter is x years old then paul is x/2
  now the present age of Paul And Peter is respectively x and (x+x/2)
  now x+x+x/2=35
  =>x=14
  so Peter is 21 years old
• 12 years agoHelpfull: Yes(0) No(5)
• short cut:
  present age of Peter:7x/4=35
  present age of Paul=:7x/3=35
  we have to calculate present age of Peter =7x=35*4=20years
• 12 years agoHelpfull: Yes(0) No(3)
• Let x-Peter's age
  y-Paul's age
  
  x+y=35
  
  x=2(y-c) where c=x-y
  Hence 3x=4y
  
  Solving the equations
  x=2= y=15
• 12 years agoHelpfull: Yes(0) No(1)
• how shorcut is working?
  
• 12 years agoHelpfull: Yes(0) No(3)