Variables R and S are related by the equation R=(1/S^2). Now is S is increased by 10%. What will happen to R?

• r=1/s^2
  r'=1/(s+0.10s)^2
  r-r'/r*100=17
  
• 13 years agoHelpfull: Yes(15) No(0)
• decrease by 17%
• 13 years agoHelpfull: Yes(8) No(1)
• Let s=10
  s'=11
  r=1/100
  r'=1/121
  decrease= (1/100-1/121)/(1/100)=17.4%
• 13 years agoHelpfull: Yes(8) No(0)
• MR. RAHUL KUMAR SAINI, R u BIO-TECH STUDENT
  
  PLz DNT MAKE FUN HERE..:)
  sarvarth sir is right
• 12 years agoHelpfull: Yes(4) No(0)
• 17.3% decrease
  
• 13 years agoHelpfull: Yes(3) No(2)
• increase 121%
• 13 years agoHelpfull: Yes(0) No(20)
• ans:17.35 (1/1^2)-(1/1.1^2)=0.17
  17%
• 8 years agoHelpfull: Yes(0) No(0)