Capgemini
Company
Numerical Ability
Permutation and Combination
Four girls Robin, Mandy, Stacy, Erica of four families Miller, Jacob, Flure and Clark prepare four salads using the fruits Apples cherries bananas, grapes .Each girls uses 3 fruits in her salad. No body have the same combination.
1 )Robin not a Miller girl uses apples.
2) Miller and Mandy uses apples and cherries.
3) Clark uses cherries and grapes but Flure uses only one of them.
4)Erica is not Clark nor Flure. htt
Then 4 questions asked.
1. Which is robins family:
a. Miller b. Jacob c.Flure d.Clark
2. Which fruit is not used by Mandy? aa
a. Cherries
b. Grapes
c. Apples
d. Bananas
3. Which is the combination by Erica?
a. Apples, cherries, Bananas
b. Apples, Cherries, Grapes
c. Apples, Grapes, Bananas
d. Cherries, Grapes, Bananas
4. Which is robin's fruit combination?
a. Apples, cherries, Bananas
b. Apples, Cherries, Grapes
c. Apples, Grapes, Bananas
d. Cherries, Grapes, Bananas
Read Solution (Total 5)
-
- I think the question is itself wrong.
Reason:
There are 4 fruits. You have to choose 3 out of 4. This can be done only in 4 ways. (Using 4C3)
All the possible 4 combinations are:
1. A C B
2. A C G
3. B G C
4. G A B
On calculation I got two correct answers. Both the answers satisfy the given conditions. So I feel there must be something wrong in the conditions or in the answer choices.
Iam not able to express my calculations.
But check out this answers with the conditions given
Ans 1 :
Girl Family Fruit combination
Mandy Jacob A C B
Erica Miller A C G
Stacy Clark B G C
Robin Flure G A B
Ans 2:
Girl FAmily Fruit combination
Mandy Flure A C B
Erica Miller A C G
Stacy Clark B G C
Robin Jacob G A B
Check out this and give me the feedback.
I will try to explain my approach.
1. As I have mentioned in the previous reply, there are 4 possible fruit combinations. Write them down
1. A C B
2. A C G
3. B G C
4. G A B
2. Now to these 4 combinations, you have to fix the girls and their families.
3. Read all the conditions and try to remember them.
4. Miller family must fit into 1st or 2nd combination (according to 2nd condition)
5. Robin does not belong to Miller family. Therefore robin does not fit into 1st and 2nd combination.
But Robin uses apple. Therefore , exactly robin fits into 4th combination.
6. Now see the 3rd condition. Flure uses only one of them between cherries and grapes. Therefore Flure family must fit into 1st or 4th combination. Now the solution splits into two possible cases. For first case assume that flure fits into 1st combination and try solving.
If we assume. that flure fits into 1st combination, the status of solution is like this:
A C B _________ Flure
A C G _________ ________
B G C _________ ________
G A B Robin _________
7. Now according to 2nd condition, Miller must fit into 2nd combination only. And according to 3rd condition , Clark must fit into 3rd condition only. Therefore Jacob will fit into the 4th combination , i.e..
A C B ________ Flure
A C G ________ Miller
B G C ________ Clark
G A B Robin Jacob
8. Now according to 4th condition, Erica must fit into 2nd combination. And according to 2nd condition Mandy must fit into the 1st combination. The left over is 3rd combination and therefore stacy fits there. i.e..
A C B Mandy Flure
A C G Erica Miller
B G C Stacy Clark
G A B Robin Jacob
That's it.. - 12 years agoHelpfull: Yes(20) No(5)
- Possible arrangement is
Mandy Flure A C B
Erica Miller A C G
Stacy Clark B G C
Robin Jacob G A B
Based on these , all questions can be answered. - 12 years agoHelpfull: Yes(9) No(4)
- WHATS THE METHOD TO SOLVE THIS TYPE OF PROBLEM..PLEASE HELP
- 12 years agoHelpfull: Yes(5) No(0)
- i don't know whether it s right or not plz make it conform whether right or wrong
robin--clark--B C G
mandy-miller--A B C
stacy-flure-- A B G
erica--jacob--A C G - 12 years agoHelpfull: Yes(2) No(13)
- 1. clark
2. grapes
3. apple grapes bananas
4. apple cherries grapes - 11 years agoHelpfull: Yes(1) No(1)
Capgemini Other Question