exam Maths Puzzle Numerical Ability

Factor completely. b^2 - ab - 6a^2

A) (b + 3a)(b - 2a)
B) (b + 6a)(b - a)
C) (b - 3a)(b + 2a)
D) (b - 6a)(b + a)

either this is a typo or I did something

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