1!+2!+3!+........+50! is divided by 5! then the remailnder is------------------? a)3 b)33 c)13 d)93...

• Clearly 5! onwards each is divisible by 5!.
  SO the remainder will come from the division (1!+2!+3!+4!) divided by 5!
  Now (1!+2!+3!+4!) = 1+2+6+24 = 33 and 5! = 120 so the remainder is 33.
• 12 years agoHelpfull: Yes(35) No(3)
• 5! onwards all are having 0,s in their units place,
  so all r divisible by 5 and gives remainder 0.
  remaing (1!+2!+3!+4!)/5=33/5=3
  ans is option (a)
• 12 years agoHelpfull: Yes(4) No(12)
• (1!+2!+3!+4!)/5!+5!/5!+6!/5!+....
  here 6!=6*5! so something*5!/5! remainder is 0
  so ans is=1!+2!+3!+4!=33
• 12 years agoHelpfull: Yes(4) No(0)