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A person run from A to B.He took ΒΌ of the time less to reach B when compare to run at normal Speed. By what percentage he has increased his speed?
a) 40 b) 44.4 c) 33.3 d) 22.2
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- ans is 33.3%
- 9 years agoHelpfull: Yes(4) No(3)
- let normal time be t, speed s
here time is reduced to ( t - t/4 ) = 3/4 * t
speed is inversely proportion to time so speed is increased to 4/3 * s
speed is increased by 4/3*s - s = 1/3 * s means 33.3% - 9 years agoHelpfull: Yes(4) No(0)
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