solve
[2+1][2^2+1][2^4+1][2^8+1][2^16+1]...........[2^256+1]

• [2+1] can be written as=[2^2-1]
  [2+1][2^2+1] can be written as=(2^4-1)
  thus
  [2+1][2^2+1]
  2^4+1)(2^8+1)(2^16+1)....[2^256+1]
  can be written as=[2^512-1]
• 12 years agoHelpfull: Yes(11) No(2)
• [2+1][2^2+1][2^4+1][2^8+1][2^16+1]...........[2^256+1]
  =[3][2^2+1][2^4+1][2^8+1][2^16+1]...........[2^256+1]
  =[4-1][2^2+1][2^4+1][2^8+1][2^16+1]...........[2^256+1]
  =[4-1][4+1][2^4+1][2^8+1][2^16+1]...........[2^256+1] [since(a+b)(a-b)=a^2-b^2]
  =[16-1][2^4+1][2^8+1][2^16+1]...........[2^256+1]
  =[16-1][16+1] [2^8+1][2^16+1]...........[2^256+1]
  .
  .
  .
  in this way finally we remain with
  =[2^256-1][2^256+1]
  =2^512-1
  
• 12 years agoHelpfull: Yes(2) No(0)