sum of the digits of a 3 digit number is subtracted from the number .the resulting number is divisible by __________

• three digit no. be=100x+10y+z
  sum of the digits of a 3 digit no.= x+y+z
  resulting no.= 100x+10y+z-(x+y+z)= 99x+9y
  
  so it is divisible by 9
  
• 10 years agoHelpfull: Yes(34) No(3)
• b) 9
  let no. of as x,y,z then
  
  (100x + 10y +z) - (x+y+z) = 99x + 9y = 9*(11x+y)
  
  always divisible by 9 .
  
• 9 years agoHelpfull: Yes(4) No(0)
• The resulting number is divisible by both 3 as well as 9
  
  (100x+10y+z )-(x+y+z)
  =99x+9y
  =9(11x+1)
  the above expression is divisible by 9 as well as 3
  
• 9 years agoHelpfull: Yes(3) No(0)
• divisible by 3.
• 10 years agoHelpfull: Yes(2) No(11)
• b) 9
  let no. of as x,y,z then
  
  (100x + 10y +z) - (x+y+z) = 99x + 9y = 9*(11x+y)
  the above expression is divisible by 9 as well as 3
  
• 9 years agoHelpfull: Yes(2) No(0)
• eg:125
  sum of digits=8
  125-8=117
  1+1+7=9,divisible by 3
  
• 8 years agoHelpfull: Yes(1) No(0)