A lady runs 18 kms towards east and then 24 kms towards north.How far is she from her starting point and in which direction?

• let her starting point is x
  than( x)2 = (18)2 + (24)2
  (x)2 = 900
  x=30 and direction will be north-east.
• 9 years agoHelpfull: Yes(9) No(0)
• 30km and direc-north-east
  
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• Direction-north east & kms
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• 30 kms and in south west direction
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• (x)^2=(24)^2 + (18)^2
  x=30km
  in north-east direction
• 8 years agoHelpfull: Yes(2) No(0)
• 30 kms in north east
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• distance 30 kms
  direction north east
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• ans) 30 km .
  she is in north direction
• 9 years agoHelpfull: Yes(0) No(1)
• The lady is 30kms far from the starting position.
  With respect to starting position she is in north-east direction.
  And she is facing north direction
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• Consider the following diagram: /
  N / |
  | / | 24
  |/ |
  W---- x------.--E
  | 18
  |
  S
  Let the lady be at the position x initially. She walks 18 kms east and then 24 kms north. Now she is in the north-east direction at a distance of square root(18^2 +24^2) i.e 30 kms. (Pythagoras theorem)
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• answer is 30 (i.e) it is similar to the diagnol of the triangle so sqare root of a*a+b*b so the diagnal is obtained square root of 900 so answer is 30
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• 30 km applying pythagoras theorem.
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• She has done 42km and is in north.
• 8 years agoHelpfull: Yes(0) No(3)
• Based on pythagoras' theorem:
  Her runs make a right angle triangle as follows:-
  so (hypotense)^2=(base)^2 +(perpendicular)^2
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• starting point distance =Sq root of(24^2 + 18^2)
  =30.
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• 18^2+24^2=900, sqareroot of 900=30
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• By using Pythagoras theroem
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• By using Pythagoras theroem
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