Q. 10 play kabadi, 20 play kho kho only, 5 play both gmaes. Then how many in total?

• 10 play kabadi =>n(A)=10,
  5 play both gmaes.=> n(AnB)=5
  20 play kho kho only,=>n(B)=n(B only)+n(AnB)=20+5=25
  Total => n(AUB)= n(A)+n(B)-n(AnB)
  = 10+25-5
  = 30
• 12 years agoHelpfull: Yes(38) No(30)
• n(A U B)=n(A) + n(B) - n(A INTERSECTION B)
  TOTAL = 10 + 20 - 5
  TOTAL = 25.
• 12 years agoHelpfull: Yes(37) No(13)
• Total = 10+20-5 = 25
• 12 years agoHelpfull: Yes(6) No(5)
• simple
  u have to find AUB=A+B+A intersection B
  AUB=10+20-5
  =25
• 12 years agoHelpfull: Yes(4) No(5)
• total=10+20-5=25(ans)
• 12 years agoHelpfull: Yes(4) No(2)
• Ans: 30
  
  Kabaddi Only=Kabaddi - Both=10-5=5
  Khokho Only=5, Both=5
  Peope don't play=0 (As not mentioned)
  Total=Kabaddi Only+ khokho Only+Both+People don't play
  =5 +20 +5 +0
  Total =30
• 8 years agoHelpfull: Yes(3) No(1)
• 10+20-5=25
  
• 12 years agoHelpfull: Yes(2) No(4)
• note that it is written 20 play kho kho ONLY
• 10 years agoHelpfull: Yes(1) No(0)
• Observe carefully... 20 play kho kho ONLY...
  so 10 play kabadi
  20 kho kho
  5 play both..
  so 10+20+5=35 is the total
• 10 years agoHelpfull: Yes(1) No(4)
• n(A U B)=n(A) + n(B) - n(A ^ B) = 10 + 20 - 5= 25.
• 11 years agoHelpfull: Yes(0) No(0)
• can anyone tell me which one is corect for above question 25 r 30??
• 10 years agoHelpfull: Yes(0) No(3)