Q. 200 pupil total,out of 125 like pizza,115 like burger, then how many like both?

• n(A U B)=n(A) + n(B) - n(A INTERSECTION B)
  200 = 125 + 115 - BOTH
  BOTH = 240 - 200 = 40.
• 12 years agoHelpfull: Yes(50) No(0)
• n(a)=pizza, n(b)=burger.
  n(aUb)=n(a)+n(b)-n(anb)
  200=125+115-n(anb)
  200=240-n(anb)
  n(anb)=240-200=>40
• 12 years agoHelpfull: Yes(9) No(0)
• (125+115-200 = 40 ) pupil like both.
• 12 years agoHelpfull: Yes(8) No(1)
• total(A union B)=200
  pizza(A)=125
  burger(B)=115
  both(A intersection B)=( |A| +|B|)-(A union B)
  = (125+115)-200
  = 240-200
  =40(ANS)
  
• 12 years agoHelpfull: Yes(8) No(0)
• No. of pupil who like both = 125+115-200 = 40
• 12 years agoHelpfull: Yes(3) No(1)
• 200=125+115-both
  both=35
• 12 years agoHelpfull: Yes(1) No(20)
• 200-(85+75)=40
• 11 years agoHelpfull: Yes(1) No(0)
• 10+20+5-4-0--2+2=31
• 10 years agoHelpfull: Yes(0) No(2)
• P(TOTAL)=P(PIZZA)+P(BURGER)-P(PIZZA AND BURGER)
  200=125+115-P(PIZZA AND BURGER)
  P(PIZZA AND BURGER)=125+115-200
  P(PIZZA AND BURGER)=240-200
  P(PIZZA AND BURGER)=40
• 10 years agoHelpfull: Yes(0) No(0)
• 200=25+115-x
  =60
  
• 10 years agoHelpfull: Yes(0) No(3)