Accenture
Company
Numerical Ability
Permutation and Combination
Q. 200 pupil total,out of 125 like pizza,115 like burger, then how many like both?
Read Solution (Total 10)
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- n(A U B)=n(A) + n(B) - n(A INTERSECTION B)
200 = 125 + 115 - BOTH
BOTH = 240 - 200 = 40. - 12 years agoHelpfull: Yes(50) No(0)
- n(a)=pizza, n(b)=burger.
n(aUb)=n(a)+n(b)-n(anb)
200=125+115-n(anb)
200=240-n(anb)
n(anb)=240-200=>40 - 12 years agoHelpfull: Yes(9) No(0)
- (125+115-200 = 40 ) pupil like both.
- 12 years agoHelpfull: Yes(8) No(1)
- total(A union B)=200
pizza(A)=125
burger(B)=115
both(A intersection B)=( |A| +|B|)-(A union B)
= (125+115)-200
= 240-200
=40(ANS)
- 12 years agoHelpfull: Yes(8) No(0)
- No. of pupil who like both = 125+115-200 = 40
- 12 years agoHelpfull: Yes(3) No(1)
- 200=125+115-both
both=35 - 12 years agoHelpfull: Yes(1) No(20)
- 200-(85+75)=40
- 12 years agoHelpfull: Yes(1) No(0)
- 10+20+5-4-0--2+2=31
- 11 years agoHelpfull: Yes(0) No(2)
- P(TOTAL)=P(PIZZA)+P(BURGER)-P(PIZZA AND BURGER)
200=125+115-P(PIZZA AND BURGER)
P(PIZZA AND BURGER)=125+115-200
P(PIZZA AND BURGER)=240-200
P(PIZZA AND BURGER)=40 - 10 years agoHelpfull: Yes(0) No(0)
- 200=25+115-x
=60
- 10 years agoHelpfull: Yes(0) No(3)
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