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Maths Puzzle
If 4^x = 8^y, then the value of (x/y)-1 is equal to :
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- 4^x = 8^y,
2^2x= 2^3y
so
2x=3y
x/y = 3/2
(x/y)-1 = (3/2)-1= 1/2
- 12 years agoHelpfull: Yes(8) No(0)
- 4^x = 8^y
xln4 = yln8 (taking natural log on both sides)
(x/y) = ln8/ln4 = (ln4+ln2)/ln4 = 1 + (ln2/ln4) = 1+(1/2)
Thus (x/y)-1 =1/2
- 12 years agoHelpfull: Yes(1) No(1)
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