GRE
Exam
Numerical Ability
Simple & Compound Interest
A college student expects to earn at least $1,000 in interest on an initial investment of $20,000. If the money is invested for one year at interest compounded quarterly, what is the least annual interest rate that would achieve the goal?
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- Basically we are asked to find the minimum rate of interest for $20,000 under compound interest compounding quarterly such that the student can earn at least $1000. So, the student is expected to have at least $21,000 (Initial amount + Interest) after one full year.
By compound interest formula,
C.I = A * [1+(Rate in decimal/ # (Number) of Compounding)]^(# of Years * # of Compounding)
21000 = 20000 * [1 + (R/400)]^4 ........# of compounding is 4 and rate in decimal, so R/400
1.05 = [1 + (R/400)]^4
Raising to power 1/4 on both sides of the above equation,
(1.05)^(1/4) = [1 + (R/400)] ......4 * (1/4) = 1 on right side
1.0123 ≃ 1+ (R/400) ......While using GRE calculator take square root of 1.05 twice
0.0123 ≃ R/400
R ≃ 4.92
To earn a interest of $1000, the rate of interest should be 4.92% approx but the problem says "atleast" $1000.
So, the rate of interest should be greater than $1000 to meet the students expectation.
- 9 years agoHelpfull: Yes(1) No(0)
- Edit: So, the rate of interest should be greater than 4.92% to meet the students expectation.
- 9 years agoHelpfull: Yes(0) No(0)
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