Every day a cyclist meets a car at the station.The road is straight and both are travelling in the same direction. The cyclist travels with a speed of 12 mph.One day the cyclist comes late by 20 min. and meets the car 5miles before the Station. What is the speed of the car?

• If they normally meet at 8AM, then
  cyclist will reach at station on that day at 8:20 AM. But train will reach station at 8AM only.
  and he will be at at point 5 miles before station at 7.55 AM ( i.e 25 min before 8:20 AM)
  so train will take 5 mins to travel( to reach stn at 8AM) 5 miles.
  so speed of train = 60 mph.
• 12 years agoHelpfull: Yes(30) No(7)
• Dear Parag,
  
  Pls note.
  I have not mixed this qn with any other qn.
  
  According to given situation and my solution, the person will reach the station at 8.20 AM as he is late by 20 minutes, But the train will reach at station at usual time i.e. at 8.00 AM.
  
  Bur the train and cyclist met 5 miles before station.
  For reaching station at 8:20 AM, the person has to cover 5 miles after meeting time . The cyclist will cover 5 miles distance in 25 min @ 12 mph or you can say covering 1 mile in 5 minutes.
  So the cyclist will meet the train 25 mins before 8:20 AM i.e 7:55 AM at a point 5 miles before station.,
  Now the train will cover that 5 miles distance in 5 mins to reach station at 8:00 AM ( at normal time.)
  so speed of train will be 1 mile per mi or 60 miles/hr..
  If still there is any doubt, you can ask.
  I shall try to clear the doubt.
• 12 years agoHelpfull: Yes(22) No(2)
• Since the cyclist travels at 12 mph, he can cover 4 miles in 20 minutes. So he was 4 miles behind where he should have been on a normal day. So when the car passed him 5 miles before the station, he should have been 4 miles ahead of that point, or only 1 mile from the station. That means, on a normal day, the cyclist can cover the final 1 mile to the station in the same amount of time it takes the car to cover the final 5 miles to the station. So the car is going 5 times as fast as the cyclist.
  
  12 mph * 5 = 60 mph
• 12 years agoHelpfull: Yes(15) No(0)
• let's assume that a car and man normally meets at 8 am,then usual time of cyclist
  at the time of meet is 8 am. and he is 6 miles behind at 7.30 am,but when the cyclist is late,he meets at 8.20 am.therefore he six miles behind at 7.50 am.since car takes 10 minute to travel 6 miles run,so the speed of train is (6*10)
  60 mph(ans)
• 12 years agoHelpfull: Yes(11) No(8)
• @ Parag,
  Pls check.
  Your statement says
  "since car takes 10 minute to travel 6 miles run,so the speed of train is (6*10)"
  since car takes 10 minute to travel 6 miles run,so the speed of train should be 36 mph, which is not correct.
• 12 years agoHelpfull: Yes(5) No(0)
• @ aman,my friend:
  you are mixing two question,once you are taking 20 minute and then you are solving using 25 minute,and you can clarify this ques from shukuntla devi's puzzle no 38.
• 12 years agoHelpfull: Yes(2) No(1)
• sorry aman i did a little mistake
• 12 years agoHelpfull: Yes(1) No(3)
• @ Prag,
  I do not have that shukuntla devi's puzzle no 38.
  
  If u hv got that book, pls post the questions at this site so that everyone can solve the puzzles here.
• 12 years agoHelpfull: Yes(1) No(1)
• i cnt guerss
• 12 years agoHelpfull: Yes(0) No(0)
• the speed of train is (6*10)
  60 mph(ans)
  
• 10 years agoHelpfull: Yes(0) No(1)