If m is an odd integer and n is an even integer then which of the following is definitely odd?
1. (2m+n)(m-n)
2. (m+n^2)+(m-n^2)
3. m^2 +mn+n^2
4. m+n

• 4) m+n should be the ans
• 11 years agoHelpfull: Yes(16) No(2)
• 3. m^2 +mn+n^2 is also odd.
• 11 years agoHelpfull: Yes(9) No(2)
• its m+n , since odd + even = odd chk usin examples
  
• 11 years agoHelpfull: Yes(9) No(1)
• m+n is right answer(sum of one even and one odd number gives always odd number)
  
  others is why not
  1.(2m+n)(m-n) -> multiply by 2 to any odd number it gives even number so (2m+n) is definitely even number and any odd number if multiply by even number result is always even
  2.(m+n^2)+(m-n^2) -> is also even number because sum off any two
  odd number is always even
  difference and addition of any two different(one even or another odd or viceversa) numbers is always odd
  3.m^2 + mn + n^2 -> is also an even number
• 11 years agoHelpfull: Yes(6) No(7)
• i think that option 4 is true
• 11 years agoHelpfull: Yes(4) No(2)
• 3.m^2+mn+n^2
  
  let m=3,n=2
  so 3^2+3*2+2^2
  9+6+4=19
• 11 years agoHelpfull: Yes(3) No(1)
• m^2 +mn+n^2
• 11 years agoHelpfull: Yes(3) No(1)
• m+n is odd
• 8 years agoHelpfull: Yes(0) No(0)