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Numerical Ability
Averages
consider the sequence 1,-2,3,-4,5,-6...... what is the average of the first 200 terms of sequence?
a. -0.5
b. -1
c. 0
d. 0.5
Read Solution (Total 15)
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- a )ans -0.5
- 9 years agoHelpfull: Yes(13) No(0)
- (1-2=-1)+ (3-4=-1)+...............(199-200=-1)=100(-1)/200=-0.5
- 9 years agoHelpfull: Yes(13) No(2)
- 1,-2,3,-4,5,-6.....-200
(1+3+5+7...199)+(-2-4-6.....-200)
this is both AP so average of AP
(a+b)/2
( 1+199)/2+(-2-200)/2=100+(-101)=-1
so ans is (b) - 9 years agoHelpfull: Yes(4) No(7)
- (1+-2)=-1
(3+-4)=-1
similarly 100 terms so the sum is -100
avarage=-100/200
-.5
ans a - 9 years agoHelpfull: Yes(3) No(0)
- 1-2= -1+ 3-4= -1 + .............+ 199-200= 200(-1)/200=-1
- 9 years agoHelpfull: Yes(1) No(6)
- ans-a. - 0.5
- 9 years agoHelpfull: Yes(1) No(0)
- s/t=a
-100/200=-0.5 - 9 years agoHelpfull: Yes(1) No(0)
- Every time two terms are going to subtract then -1 are 100 in number
Then sum of such 100 numbers and whole divided by 200 biz we r dividing 200 before
Simplification . So ( -1-1-1-1.....-1 which are sum of- 100)% total
Numbers is 200 and is 0.5 - 9 years agoHelpfull: Yes(0) No(1)
- it consists of two series...
1,3,5,......and -2,-4,-6,......
first find the sums of the series and find the avg ans is -0.5 - 9 years agoHelpfull: Yes(0) No(0)
- -100/200 = -0.5
- 9 years agoHelpfull: Yes(0) No(0)
- use s=n(a+l)/2={50*(1+199)-50*(2+200)}/200
- 9 years agoHelpfull: Yes(0) No(0)
- Ans: -0.5
Sum of 100 odd terms = 10000
Sum of 100 even -ve terms=-10100
Average=(-10100+10000)/200=-0.5
- 9 years agoHelpfull: Yes(0) No(0)
- these are Consecutive number the difference between the number is = -1
the average of 200 terms is = -1/2=-0.5 - 9 years agoHelpfull: Yes(0) No(0)
- In consicutive 2 munber sum is -1.So in first 200 term sum will be -100.So the average is -0.5.
- 9 years agoHelpfull: Yes(0) No(0)
- -0.5
- 9 years agoHelpfull: Yes(0) No(0)
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