the prime factorization of an integer N is A*A*B*C where A,B,C are all distinct integers.how many factors does N have?
a)12
b)24
c)4
c)6

• N = (A^2)*B*C
  Assuming A , B, C are prime numbers we get ,
  NUMBER OF FACTORS ON N = (2+1)*(1+1)*(1+1)= 12
  
  So, correct answer is a)12
  
  N.B.: Though in the problem statement , is not explicitly mentioned that A , B, C are distinct PRIME NUMBERS ,but unless we ASSUME this condition on A ,B , C
  then the problem can't be solved.So the above solution involves this mentioned and of course necessary assumption.
• 12 years agoHelpfull: Yes(28) No(4)