From the cards jack,queen,king and ace are removed.Then the algebraic sum of rest of cards will be?

• 216
  2+3+......+10=54
  54x4=216
• 9 years agoHelpfull: Yes(13) No(1)
• cards =4 [ 1,2,3----------------------13 ]
  now jack =11, queen = 12 king = 13& ace = 1 are removed
  so sum = 4 [ 2.3.4.5.-----------------10]
  = 4 [ 9/2( 2+ 10)] [ sum of A. P.is-- Sn = n/2( a1 + an ]
  = 4*9/2* 12= 216 ans
  
• 9 years agoHelpfull: Yes(2) No(0)
• total no of card 52
  16 are removed so remaining 36 cards
  sn=n/2(a1+an)
  =36/2 (2+10)=216
• 9 years agoHelpfull: Yes(2) No(0)
• jack,queen,king,ace total 22 card remove
  then heart 1-10 total= 55, club 1-10 total=55, diamonds 1-10 total=55
  55+55+55=165 ans.
• 9 years agoHelpfull: Yes(0) No(8)
• 4*2=8
  4*3=12
  .
  .
  .
  4*10=40
  now take sum of A.P. with cd 4.
  ie n/2(a+l)
  9/2(8+40)=216 ans.
• 9 years agoHelpfull: Yes(0) No(0)