Using the digits 1,5,2,8 four digit numbers are formed.The sum of all possible such numbers are..
a)100002 b)106656 c)3400005 d)500000

• formula for finding sum of all n digit=
  n-1! * (sum of n digits) * 1111
  
  here n=no of digits=4(1,5,2,8)
  
  =3!*16*1111 =106656
  
  
• 9 years agoHelpfull: Yes(18) No(0)
• For this when we put 1/5/2/8 at unit place i.e _ _ _ 8 ,_ _ _ 2 , _ _ _ 5 , _ _ _ 1 we can fill the remaining in 3*2*1 ways = 6 ways i.e 8 get in repeated at unit place for 6 times and the same could said for 1,2,5 . and hence unit digit be 6( 8 + 5 + 1 +2) and hence unit place will come up as 6 and from option u will get a clear answer as 106656.
• 9 years agoHelpfull: Yes(17) No(0)
• (b).1+5+2+8=16 4!=24>>>no of nos that can be formed
  
  24/4=6
  
  6*16=96
  
  96 * 96(10)*96(100)*96(1000)=106656
• 9 years agoHelpfull: Yes(5) No(0)
• 106656 is the ans
• 9 years agoHelpfull: Yes(4) No(0)
• there are 3*2*1=6 ways to place a particular digit at a particular place,
  so the sum=6*(1+5+2+8)*1000+6*(1+5+2+8)*100+6*(1+5+2+8)*10+6*(1+5+2+8)*1
  =96000+9600+960+96
  =106656
• 9 years agoHelpfull: Yes(2) No(0)